1/6(2/5)^x

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Solution for 1/6(2/5)^x equation: 


x in (-oo:+oo)

(1/6)*(2/5)^x = 0

1/6 = 0

1/6 = 0 // * 6

1 = 0

(2/5)^x = 0

x należy do O

(1/6)*(2/5)^x = 0  <=>  1/6 = 0 or (1/6)*(2/5)^x = 0  <=>  (2/5)^x = 0

x belongs to the empty set

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